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/* Test for memory handling in regex.
Copyright (C) 2002 Free Software Foundation, Inc.
This file is part of the GNU C Library.
Contributed by Ulrich Drepper <drepper@redhat.com>, 2001.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, write to the Free
Software Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
02110-1301 USA. */
#ifdef HAVE_CONFIG_H
#include "config.h"
#endif
#include <sys/types.h>
#ifdef HAVE_MCHECK_H
#include <mcheck.h>
#endif
#include <regex.h>
#include <stdio.h>
#include <stdlib.h>
static const char text[] = "#! /bin/sh";
int
main (void)
{
regex_t re;
regmatch_t rm[2];
int n;
#ifdef HAVE_MCHECK_H
mtrace ();
#endif
n = regcomp (&re, "^#! */.*/(k|ba||pdk|z)sh", REG_EXTENDED);
if (n != 0)
{
char buf[500];
regerror (n, &re, buf, sizeof (buf));
printf ("regcomp failed: %s\n", buf);
exit (1);
}
for (n = 0; n < 20; ++n)
{
if (regexec (&re, text, 2, rm, 0))
{
puts ("regexec failed");
exit (2);
}
if (rm[0].rm_so != 0 || rm[0].rm_eo != 10
|| rm[1].rm_so != 8 || rm[1].rm_eo != 8)
{
printf ("regexec match failure: %d %d %d %d\n",
rm[0].rm_so, rm[0].rm_eo, rm[1].rm_so, rm[1].rm_eo);
exit (3);
}
}
regfree (&re);
return 0;
}
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